Question

fill in the name and empirical formula of each ionic compound that could be formed from the ions in this table:

		some ionic compounds
$nh_{4}^{+}$	$clo_{3}^{-}$	$square$	$square$
$na^{+}$	$io_{2}^{-}$	$square$	$square$
$na^{+}$	$io_{3}^{-}$	$square$	$square$

Explanation:

Step1: Determine empirical formula for $NH_4^+$ and $ClO_3^-$

The charges of $NH_4^+$ is + 1 and $ClO_3^-$ is - 1. The empirical formula is $NH_4ClO_3$.

Step2: Name the compound for $NH_4^+$ and $ClO_3^-$

The name is ammonium chlorate.

Step3: Determine empirical formula for $Na^+$ and $IO_2^-$

The charges of $Na^+$ is + 1 and $IO_2^-$ is - 1. The empirical formula is $NaIO_2$.

Step4: Name the compound for $Na^+$ and $IO_2^-$

The name is sodium iodite.

Step5: Determine empirical formula for $Na^+$ and $IO_3^-$

The charges of $Na^+$ is + 1 and $IO_3^-$ is - 1. The empirical formula is $NaIO_3$.

Step6: Name the compound for $Na^+$ and $IO_3^-$

The name is sodium iodate.

Answer:

cation	anion	empirical formula	name of compound
$Na^+$	$IO_2^-$	$NaIO_2$	sodium iodite
$Na^+$	$IO_3^-$	$NaIO_3$	sodium iodate