Question

fill in the name and empirical formula of each ionic compound that could be formed from the ions in this table: some ionic compounds cation anion empirical formula name of compound fe^{3 +} bro_{3}^{-} co^{3 +} clo_{3}^{-} cu^{+} io_{3}^{-} mn^{3 +} so_{4}^{2 -}

Explanation:

Step1: Determine formula for $Fe^{3 +}$ and $BrO_{3}^{-}$

The charges must balance. Three $BrO_{3}^{-}$ are needed for one $Fe^{3+}$. So the empirical formula is $Fe(BrO_{3})_{3}$, and the name is iron(III) bromate.

Step2: Determine formula for $Co^{3 +}$ and $ClO_{3}^{-}$

Three $ClO_{3}^{-}$ are needed for one $Co^{3+}$ to balance charges. The empirical formula is $Co(ClO_{3})_{3}$, and the name is cobalt(III) chlorate.

Step3: Determine formula for $Cu^{+}$ and $IO_{3}^{-}$

The charges are already balanced with a 1:1 ratio. The empirical formula is $CuIO_{3}$, and the name is copper(I) iodate.

Step4: Determine formula for $Mn^{3 +}$ and $SO_{4}^{2 -}$

Two $Mn^{3+}$ and three $SO_{4}^{2 -}$ are needed to balance charges. The empirical formula is $Mn_{2}(SO_{4})_{3}$, and the name is manganese(III) sulfate.

Answer:

cation	anion	empirical formula	name of compound
$Co^{3+}$	$ClO_{3}^{-}$	$Co(ClO_{3})_{3}$	cobalt(III) chlorate
$Cu^{+}$	$IO_{3}^{-}$	$CuIO_{3}$	copper(I) iodate
$Mn^{3+}$	$SO_{4}^{2 -}$	$Mn_{2}(SO_{4})_{3}$	manganese(III) sulfate