Question

fill in the table using this function rule.
y = 10x - 2

x	y
-1	□
0	□
1	□
5	□

Explanation:

Step1: Substitute \( x = -1 \) into \( y = 10x - 2 \)

\( y = 10\times(-1) - 2 = -10 - 2 = -12 \)

Step2: Substitute \( x = 0 \) into \( y = 10x - 2 \)

\( y = 10\times0 - 2 = 0 - 2 = -2 \)

Step3: Substitute \( x = 1 \) into \( y = 10x - 2 \)

\( y = 10\times1 - 2 = 10 - 2 = 8 \)

Step4: Substitute \( x = 5 \) into \( y = 10x - 2 \)

\( y = 10\times5 - 2 = 50 - 2 = 48 \)

Answer:

When \( x = -1 \), \( y = -12 \); when \( x = 0 \), \( y = -2 \); when \( x = 1 \), \( y = 8 \); when \( x = 5 \), \( y = 48 \). So the completed table is:

\( x \)	\( y \)
\( 0 \)	\( -2 \)
\( 1 \)	\( 8 \)
\( 5 \)	\( 48 \)