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find the 98th term of the arithmetic sequence 8, 24, 40, ...

Question

find the 98th term of the arithmetic sequence 8, 24, 40, ...

Explanation:

Step1: Identify sequence parameters

First term $a_1 = 8$, common difference $d = 24 - 8 = 16$, target term $n = 98$.

Step2: Use arithmetic term formula

The formula for the $n$th term of an arithmetic sequence is $a_n = a_1 + (n - 1)d$.
Substitute values: $a_{98} = 8 + (98 - 1) \times 16$

Step3: Calculate the result

Simplify the expression:
$a_{98} = 8 + 97 \times 16 = 8 + 1552$

Answer:

1560