Question

find all the factor pairs for 78 and complete the equations. each equation should use a different pair of factors. 78 = \square \cdot 78 78 = 2 \cdot \square 78 = \square \cdot \square 78 = \square \cdot \square

Explanation:

Step1: Find the first factor

To find the missing factor in \(78=\square\cdot78\), we know that any number multiplied by 1 is itself. So the missing factor is 1.
\(78 = 1\cdot78\)

Step2: Find the second factor

For \(78 = 2\cdot\square\), we divide 78 by 2. \(78\div2 = 39\). So the missing factor is 39.
\(78 = 2\cdot39\)

Step3: Find the third factor pair

We start checking numbers. 3 times 26 is 78 (\(3\times26 = 78\)). So we can write \(78 = 3\cdot26\)

Step4: Find the fourth factor pair

Next, 6 times 13 is 78 (\(6\times13 = 78\)). So we can write \(78 = 6\cdot13\)

Answer:

\(78 = \boldsymbol{1}\cdot78\)
\(78 = 2\cdot\boldsymbol{39}\)
\(78 = \boldsymbol{3}\cdot\boldsymbol{26}\)
\(78 = \boldsymbol{6}\cdot\boldsymbol{13}\)