Question

1. find the area of the figure.

\\(\frac{16}{3}\\) yd
\\(\frac{3}{4}\\) yd
\\( 7\frac{1}{9} \text{ yd}^2 \\)
\\( 4 \text{ yd}^2 \\)
\\( 12\frac{1}{6} \text{ yd}^2 \\)
\\( 4\frac{1}{6} \text{ yd}^2 \\)

Explanation:

Step1: Recall parallelogram area formula

Area = base × height, where base $b=\frac{16}{3}$ yd, height $h=\frac{3}{4}$ yd

Step2: Substitute values into formula

$\text{Area} = \frac{16}{3} \times \frac{3}{4}$

Step3: Simplify the expression

$\text{Area} = \frac{16 \times 3}{3 \times 4} = 4$

Answer:

4 yd²