QUESTION IMAGE
Question
find the coordinates of the vertices of the polygon after the given translation to a new position in the plane. original point translated point (-3,6) (x,y)=(2,3)× (-5,3) (x,y)=(2,-5)× (-1,3) (x,y)=(4,0)× (-3,0) (x,y)=(4,-3)×
Step1: Identify translation rule
The polygon is translated 6 units right and 3 units down. For a point $(x,y)$, the new - point after translation is $(x + 6,y-3)$.
Step2: Translate point $(-3,6)$
For the point $(-3,6)$, $x=-3$ and $y = 6$. Using the translation rule $(x + 6,y - 3)$, we have $x=-3+6 = 3$ and $y=6 - 3=3$. So the new point is $(3,3)$.
Step3: Translate point $(-5,3)$
For the point $(-5,3)$, $x=-5$ and $y = 3$. Using the translation rule $(x + 6,y - 3)$, we have $x=-5+6 = 1$ and $y=3 - 3=0$. So the new point is $(1,0)$.
Step4: Translate point $(-1,3)$
For the point $(-1,3)$, $x=-1$ and $y = 3$. Using the translation rule $(x + 6,y - 3)$, we have $x=-1+6 = 5$ and $y=3 - 3=0$. So the new point is $(5,0)$.
Step5: Translate point $(-3,0)$
For the point $(-3,0)$, $x=-3$ and $y = 0$. Using the translation rule $(x + 6,y - 3)$, we have $x=-3+6 = 3$ and $y=0 - 3=-3$. So the new point is $(3,-3)$.
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| Original Point | Translated Point |
|---|---|
| $(-5,3)$ | $(1,0)$ |
| $(-1,3)$ | $(5,0)$ |
| $(-3,0)$ | $(3,-3)$ |