QUESTION IMAGE
Question
find the distance between each pair of points.
5.
6.
- $k(2, 3), f(4, 4)$
- $c(-3, -1), q(-2, 3)$
- $y(2, 0), p(2, 6)$
- $w(-2, 2), r(5, 2)$
- $a(-7, -3), b(5, 2)$
- $c(-3, 1), q(2, 6)$
The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$. For vertical/horizontal points, we can also use direct difference of coordinates.
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Problem 5: $F(-3,-2)$, $G(1,1)$
Step1: Identify coordinates
$x_1=-3,y_1=-2; x_2=1,y_2=1$
Step2: Apply distance formula
$d=\sqrt{(1-(-3))^2+(1-(-2))^2}=\sqrt{4^2+3^2}$
Step3: Calculate final value
$\sqrt{16+9}=\sqrt{25}=5$
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Problem 6: $D(-2,-4)$, $S(4,2)$
Step1: Identify coordinates
$x_1=-2,y_1=-4; x_2=4,y_2=2$
Step2: Apply distance formula
$d=\sqrt{(4-(-2))^2+(2-(-4))^2}=\sqrt{6^2+6^2}$
Step3: Calculate final value
$\sqrt{36+36}=\sqrt{72}=6\sqrt{2}$
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Problem 7: $K(2,3)$, $F(4,4)$
Step1: Identify coordinates
$x_1=2,y_1=3; x_2=4,y_2=4$
Step2: Apply distance formula
$d=\sqrt{(4-2)^2+(4-3)^2}=\sqrt{2^2+1^2}$
Step3: Calculate final value
$\sqrt{4+1}=\sqrt{5}$
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Problem 8: $C(-3,-1)$, $Q(-2,3)$
Step1: Identify coordinates
$x_1=-3,y_1=-1; x_2=-2,y_2=3$
Step2: Apply distance formula
$d=\sqrt{(-2-(-3))^2+(3-(-1))^2}=\sqrt{1^2+4^2}$
Step3: Calculate final value
$\sqrt{1+16}=\sqrt{17}$
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Problem 9: $Y(2,0)$, $P(2,6)$
Step1: Note vertical alignment (same x)
$d=|y_2-y_1|$
Step2: Compute vertical difference
$|6-0|=6$
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Problem 10: $W(-2,2)$, $R(5,2)$
Step1: Note horizontal alignment (same y)
$d=|x_2-x_1|$
Step2: Compute horizontal difference
$|5-(-2)|=7$
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Problem 11: $A(-7,-3)$, $B(5,2)$
Step1: Identify coordinates
$x_1=-7,y_1=-3; x_2=5,y_2=2$
Step2: Apply distance formula
$d=\sqrt{(5-(-7))^2+(2-(-3))^2}=\sqrt{12^2+5^2}$
Step3: Calculate final value
$\sqrt{144+25}=\sqrt{169}=13$
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Problem 12: $C(-3,1)$, $Q(2,6)$
Step1: Identify coordinates
$x_1=-3,y_1=1; x_2=2,y_2=6$
Step2: Apply distance formula
$d=\sqrt{(2-(-3))^2+(6-1)^2}=\sqrt{5^2+5^2}$
Step3: Calculate final value
$\sqrt{25+25}=\sqrt{50}=5\sqrt{2}$
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