Question

find the distance between v(4, 4) and x(5, 8). round to the nearest tenth, if necessary.

Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $(x_1,y_1)=(4,4)$ and $(x_2,y_2)=(5,8)$.

Step2: Substitute values

$d=\sqrt{(5 - 4)^2+(8 - 4)^2}=\sqrt{1^2+4^2}=\sqrt{1 + 16}=\sqrt{17}$.

Step3: Calculate and round

$\sqrt{17}\approx4.1$.

Answer:

$4.1$