Question

find the equation of a line parallel to y = 4x - 4 that passes through the point (-9, -8).
answer
y = 4x + 28\ty = 1/4x - 4\ty = -1/4x - 4\ty = -4x + 28

Explanation:

Step1: Determine the slope

Parallel lines have equal slopes. The slope of the line $y = 4x-4$ is $m = 4$, so the slope of the new line is also $m = 4$.

Step2: Use the point - slope form

The point - slope form of a line is $y - y_1=m(x - x_1)$, where $(x_1,y_1)=(-9,-8)$ and $m = 4$. Substitute these values: $y-(-8)=4(x - (-9))$.

Step3: Simplify the equation

$y + 8=4(x + 9)$. Expand the right - hand side: $y+8 = 4x+36$. Then, solve for $y$: $y=4x + 36-8$, which simplifies to $y = 4x+28$.

Answer:

$y = 4x + 28$