Question

find an equation that meets the conditions p varies inversely as d, and p = 5 when d = 3.
p = \square (simplify your answer.)

Explanation:

Step1: Recall inverse variation formula

If \( p \) varies inversely as \( d \), the formula is \( p=\frac{k}{d} \), where \( k \) is the constant of variation.

Step2: Find the constant \( k \)

We know \( p = 5 \) when \( d=3 \). Substitute these values into the formula: \( 5=\frac{k}{3} \). Multiply both sides by 3: \( k = 5\times3=15 \).

Step3: Write the equation

Substitute \( k = 15 \) back into the inverse variation formula: \( p=\frac{15}{d} \).

Answer:

\( \frac{15}{d} \)