Question

find the error a student was evaluating 4b + c for b = 2 and c = 3. find the student’s mistake and correct it. 4b + c = 4(3) + 2 = 12 + 2 = 14

Explanation:

Step1: Identify the mistake

The student mixed up the values of \( b \) and \( c \). They used \( b = 3 \) and \( c = 2 \) instead of \( b = 2 \) and \( c = 3 \).

Step2: Substitute correct values

Substitute \( b = 2 \) and \( c = 3 \) into the expression \( 4b + c \).
\[
4b + c = 4(2) + 3
\]

Step3: Calculate the result

First, calculate \( 4(2) = 8 \), then add \( 3 \):
\[
8 + 3 = 11
\]

Answer:

The student's mistake was substituting \( b = 3 \) and \( c = 2 \) instead of \( b = 2 \) and \( c = 3 \). The correct value of \( 4b + c \) when \( b = 2 \) and \( c = 3 \) is \( 11 \).