Question

1. \\(\bigcirc a = 2a + 4\\)

\\(\square b = \frac{b + 6}{2}\\)
find \\(\square\bigcirc 6\\) (the expression represented by the box containing a circle containing 6, following the operation rules of \\(\bigcirc a\\) and \\(\square b\\))

Explanation:

Step1: Evaluate the square function for \( b = 6 \)

The square function is \( \boxed{b} = \frac{b + 6}{2} \). Substitute \( b = 6 \) into this function:
\[
\frac{6 + 6}{2} = \frac{12}{2} = 6
\]

Step2: Evaluate the circle function with the result from Step1

The circle function is \( \bigcirc(a) = 2a + 4 \). Now, use the result from Step1 (which is \( a = 6 \)) and substitute into the circle function:
\[
2(6) + 4 = 12 + 4 = 16
\]

Answer:

16