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QUESTION IMAGE

find the following for the path in the figure below. (a) the total dist…

Question

find the following for the path in the figure below.
(a) the total distance traveled
m
(b) the displacement from start to finish
m
resources
reading

Explanation:

Response
Part (a): Total Distance Traveled

Step1: Analyze the Path Segments

The start point is at \( x = 2 \, \text{m} \) (from the origin, as the first segment starts at the red dot near \( x = 2 \)). The main horizontal segment goes from \( x = 2 \) to \( x = 10 \), then there's a small back-and-forth (a "U - turn" like shape). Let's break down the path:

  • From start (\( x = 2 \)) to the start of the U - turn: distance is \( 10 - 2=8 \, \text{m} \).
  • The U - turn: Let's assume the U - turn has two small segments. Looking at the graph, the U - turn goes from \( x = 8 \) to \( x = 10 \) (back) and then to \( x = 8 \) (forward)? Wait, no, the figure shows a path that goes straight to a point, then does a small loop (two small horizontal segments: one back, one forward) and then continues. Wait, actually, the start is at \( x = 2 \), then it goes to \( x = 10 \), then back to \( x = 8 \), then forward to \( x = 10 \), then forward to \( x = 12 \)? Wait, no, the x - axis has marks at 0, 2, 4, 6, 8, 10, 12. The start point is at \( x = 2 \). The path goes from \( x = 2 \) to \( x = 10 \) (distance \( 10 - 2 = 8 \, \text{m} \)), then back to \( x = 8 \) (distance \( 10 - 8=2 \, \text{m} \)), then forward to \( x = 10 \) (distance \( 10 - 8 = 2 \, \text{m} \)), then forward to \( x = 12 \) (distance \( 12 - 10=2 \, \text{m} \))? Wait, no, maybe a better way: the total distance is the sum of all the lengths of the path. The straight part from \( x = 2 \) to \( x = 12 \) would be \( 12 - 2 = 10 \, \text{m} \), but with the two small back - and - forth segments (each of length \( 2 \, \text{m} \), since from \( x = 8 \) to \( x = 10 \) is \( 2 \, \text{m} \), and back to \( x = 8 \) is another \( 2 \, \text{m} \), then forward to \( x = 10 \) and then to \( x = 12 \)? Wait, no, looking at the figure, the path has a start at \( x = 2 \), then goes to \( x = 10 \), then does a loop: goes back \( 2 \, \text{m} \) (to \( x = 8 \)), then forward \( 2 \, \text{m} \) (to \( x = 10 \)), then forward \( 2 \, \text{m} \) (to \( x = 12 \)). Wait, no, the correct way: the total distance is the length of the entire path. The start is at \( x = 2 \), the end is at \( x = 12 \). But the path has a detour: from \( x = 8 \) to \( x = 10 \) (forward), then back to \( x = 8 \) (backward), then forward to \( x = 10 \) and then to \( x = 12 \). Wait, actually, the horizontal distance from start (\( x = 2 \)) to the point before the loop is \( 10 - 2=8 \, \text{m} \). Then the loop: from \( x = 8 \) to \( x = 10 \) (distance \( 2 \, \text{m} \)), back to \( x = 8 \) (distance \( 2 \, \text{m} \)), then from \( x = 8 \) to \( x = 12 \) (distance \( 4 \, \text{m} \))? No, that can't be. Wait, maybe the loop is two segments: each of length \( 2 \, \text{m} \) (so total loop distance \( 2 + 2=4 \, \text{m} \)), and the straight part from \( x = 2 \) to \( x = 12 \) is \( 10 \, \text{m} \), but with the loop, the total distance is \( (12 - 2)+4=14 \, \text{m} \)? Wait, let's think again. The start is at \( x = 2 \). The path goes:
  • From \( x = 2 \) to \( x = 10 \): distance \( 10 - 2 = 8 \, \text{m} \)
  • Then from \( x = 10 \) to \( x = 8 \): distance \( 10 - 8 = 2 \, \text{m} \)
  • Then from \( x = 8 \) to \( x = 10 \): distance \( 10 - 8 = 2 \, \text{m} \)
  • Then from \( x = 10 \) to \( x = 12 \): distance \( 12 - 10 = 2 \, \text{m} \)

Now sum these up: \( 8+2 + 2+2=14 \, \text{m} \)

Step2: Sum the Distances

Add the lengths of each segment: \( 8+2 + 2+2 = 14 \, \text{m} \)

Part (b): Displacement from Start to Finish

Step1: Define Displacement

Displacement is the straight - line distance from the initial position to the final position, along with the direction (in one - dimension, it's the difference between final and initial position).

Step2: Calculate Displacement

Initial position \( x_i=2 \, \text{m} \), final position \( x_f = 12 \, \text{m} \). Displacement \( \Delta x=x_f - x_i=12 - 2 = 10 \, \text{m} \)

Answer:

(a):
\( 14 \)