Question

find the following product.
$(8y + 7)^2$

$(8y + 7)^2 = \square$

Explanation:

Step1: Apply square of sum formula

Recall the formula $(a+b)^2 = a^2 + 2ab + b^2$, where $a=8y$, $b=7$.

Step2: Calculate $a^2$

$(8y)^2 = 64y^2$

Step3: Calculate $2ab$

$2\times8y\times7 = 112y$

Step4: Calculate $b^2$

$7^2 = 49$

Step5: Combine all terms

Add the results from Steps 2-3-4.

Answer:

$64y^2 + 112y + 49$