Question

find the indicated probability. a survey revealed that 31% of people are entertained by reading books, 39% are entertained by watching tv, and 30% are entertained by both books and tv. what is the probability that a person will be entertained by either books or tv? 0.40 0.70 0.30 0.22 1

Explanation:

Step1: Recall the formula for the probability of the union of two events

The formula for \(P(A\cup B)\) is \(P(A)+P(B)-P(A\cap B)\), where \(A\) is the event of being entertained by books and \(B\) is the event of being entertained by TV.
Let \(P(A) = 0.31\), \(P(B)=0.39\) and \(P(A\cap B)=0.30\).

Step2: Substitute the values into the formula

\(P(A\cup B)=0.31 + 0.39- 0.30\)
\(P(A\cup B)=0.40\)

Answer:

0.40