Question

1. find the midpoint. the endpoints of gh are g(0, 0) and h(4, 10). find the midpoint. the endpoints of ab are a(2, 6) and b(10, 8). find the midpoint. the endpoints of qr are q(- 3, 0) and r(7, - 8). 2. name angle 4 name angle 4 and 5 name all 3 angles find the distance between c(3, 1) and m(6, 5) find the distance between g(4, 1) and f(9, 6) to the nearest hundredth. find the distance between a(7, - 4) and t(2, 3) to the nearest hundredth.

Explanation:

values
Here $x_1 = 4,y_1 = 1,x_2 = 9,y_2 = 6$. Then $d=\sqrt{(9 - 4)^2+(6 - 1)^2}=\sqrt{5^2+5^2}=\sqrt{25 + 25}=\sqrt{50}\approx7.07$.

Step1: Recall mid - point formula

The mid - point formula for two points $(x_1,y_1)$ and $(x_2,y_2)$ is $(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$.

Step2: Substitute values

Here $x_1=-3,y_1 = 0,x_2 = 7,y_2=-8$. So the mid - point is $(\frac{-3 + 7}{2},\frac{0-8}{2})=(2,-4)$.

The three angles are $\angle KVL,\angle LVM,\angle KVM$.

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$.

Step2: Substitute values

Here $x_1 = 7,y_1=-4,x_2 = 2,y_2 = 3$. Then $d=\sqrt{(2 - 7)^2+(3+4)^2}=\sqrt{(-5)^2+7^2}=\sqrt{25 + 49}=\sqrt{74}\approx8.60$.

Answer:

$7.07$

Spicy (100%)

1. Find the midpoint. The endpoints of $\overline{QR}$ are $Q(-3,0)$ and $R(7,-8)$.