Question

1. find the missing values of the table. round to the nearest thousandth (3 decimal places)

rental car prices for a family of 4 frequency relative frequency cumulative frequency relative cumulative frequency
$478 2.074 2.074
$570 3 a. 5.185
$610 4.148 c. e.
$675 6.223 15.556
$705 4.148 19 f.
$892 5 b. 24.889
$1,094 3.111 d. 1

Explanation:

Step1: Calculate relative frequency for $570

Relative frequency = $\frac{\text{Frequency}}{\text{Total frequency}}$. First, find total frequency. From the first - row, if relative frequency of $478$ is $0.074$ and frequency is $2$, then total frequency $N=\frac{2}{0.074}\approx27$. For $570$ with frequency $3$, relative frequency $a = \frac{3}{27}\approx0.111$.

Step2: Calculate relative frequency for $892

For $892$ with frequency $5$, relative frequency $b=\frac{5}{27}\approx0.185$.

Step3: Calculate cumulative frequency for $610

Cumulative frequency for $610$ is the sum of frequencies of all previous values and the frequency of $610$ itself. Since previous cumulative frequency is $5$ and frequency of $610$ is $4$, $c = 5 + 4=9$.

Step4: Calculate cumulative frequency for $1094

Since the last relative cumulative frequency is $1$, the total cumulative frequency $d = 27$.

Step5: Calculate relative cumulative frequency for $610

Relative cumulative frequency for $610$ is the cumulative frequency of $610$ divided by total frequency. So $e=\frac{9}{27}=0.333$.

Step6: Calculate relative cumulative frequency for $705

Relative cumulative frequency for $705$ is $\frac{19}{27}\approx0.704$. So $f = 0.704$.

Answer:

a. $0.111$
b. $0.185$
c. $9$
d. $27$
e. $0.333$
f. $0.704$