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2) find the outlier of the data set. 40, 62, 47, 68, 12, 78, 49, 65, 49…

Question

  1. find the outlier of the data set. 40, 62, 47, 68, 12, 78, 49, 65, 49, 52, 63

Explanation:

Step1: Arrange data in ascending order

$12,40,47,49,49,52,62,63,65,68,78$

Step2: Calculate the median (Q2)

There are 11 data - points. The median is the 6th value. So, $Q2 = 52$.

Step3: Calculate the lower half and its median (Q1)

The lower half is $12,40,47,49,49$. The median of the lower half (Q1) is 47.

Step4: Calculate the upper half and its median (Q3)

The upper half is $62,63,65,68,78$. The median of the upper half (Q3) is 65.

Step5: Calculate the inter - quartile range (IQR)

$IQR=Q3 - Q1=65 - 47 = 18$

Step6: Calculate the lower and upper bounds for non - outliers

Lower bound: $Q1-1.5\times IQR=47-1.5\times18=47 - 27=20$
Upper bound: $Q3 + 1.5\times IQR=65+1.5\times18=65 + 27=92$

Step7: Identify the outlier

The value 12 is less than 20. So, 12 is the outlier.

Answer:

12