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find the perimeter and area of the figure below. triangle with side len…

Question

find the perimeter and area of the figure below.

triangle with side lengths 424, 257, base 453, and height 236

perimeter =

area =

Explanation:

Step1: Calculate the perimeter

The perimeter of a triangle is the sum of its three sides. The sides are 424, 453, and 257.
$Perimeter = 424 + 453 + 257$
First, add 424 and 453: $424 + 453 = 877$
Then, add 877 and 257: $877 + 257 = 1134$

Step2: Calculate the area

The area of a triangle is given by the formula $Area = \frac{1}{2} \times base \times height$. Here, the base is 453 and the height is 236.
$Area = \frac{1}{2} \times 453 \times 236$
First, calculate $453 \times 236$: $453 \times 236 = 106908$
Then, divide by 2: $\frac{106908}{2} = 53454$

Answer:

Perimeter = 1134
Area = 53454