Question

find the perimeter of the quadrilateral. if x = 2, the perimeter is inches. (4x² + 8x) in. 31 in. (3x² - 5x + 20) in. (7x + 30) in.

Explanation:

Step1: Sum all side lengths

$Perimeter = (4x^2 + 8x) + 31 + (7x + 30) + (3x^2 - 5x + 20)$

Step2: Combine like terms

$Perimeter = (4x^2+3x^2) + (8x+7x-5x) + (31+30+20) = 7x^2 + 10x + 81$

Step3: Substitute $x=2$

$Perimeter = 7(2)^2 + 10(2) + 81 = 7(4) + 20 + 81$

Step4: Calculate final value

$Perimeter = 28 + 20 + 81$

Answer:

129 inches