Question

1. find pq, qr, and pr.

pq =
qr =
pr =

Explanation:

Step1: Observe the line - segment relationship

We know that $PR=PQ + QR$. Given $PQ = 9y-2$, $QR=14 + 5y$, and $PR=(9y - 2)+(14 + 5y)$.

Step2: Simplify the expression for $PR$

Combine like - terms: $PR=(9y+5y)+(-2 + 14)=14y + 12$.
Since $PR$ is also the sum of $PQ$ and $QR$, we have:
$PQ=9y-2$
$QR=14 + 5y$
$PR=14y + 12$

Answer:

$PQ = 9y-2$
$QR=14 + 5y$
$PR=14y + 12$