Question

find the product of the following two matrices.\

$$\begin{bmatrix}-5&0\\\\0&4\\end{bmatrix}$$

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$$\begin{bmatrix}1&1\\\\3&3\\end{bmatrix}$$

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answer attempt 1 out of 99\
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$$\begin{bmatrix}\\square&\\square\\\\\\square&\\square\\end{bmatrix}$$

Explanation:

Step1: Multiply first row of first matrix with first column of second matrix.

To find the element in the first row and first column of the product matrix, we calculate $(-5)\times1 + 0\times3$.
$(-5)\times1 + 0\times3=-5 + 0=-5$

Step2: Multiply first row of first matrix with second column of second matrix.

For the element in the first row and second column, we calculate $(-5)\times1 + 0\times3$.
$(-5)\times1 + 0\times3=-5 + 0=-5$

Step3: Multiply second row of first matrix with first column of second matrix.

To find the element in the second row and first column, we calculate $0\times1 + 4\times3$.
$0\times1 + 4\times3=0 + 12=12$

Step4: Multiply second row of first matrix with second column of second matrix.

For the element in the second row and second column, we calculate $0\times1 + 4\times3$.
$0\times1 + 4\times3=0 + 12=12$

Answer:

$$\begin{bmatrix}-5&-5\\12&12\end{bmatrix}$$