Question

find the product. write your answer in standard form.
$(2y - 11)(y^2 - 3y + 2)$

Explanation:

Step1: Distribute $2y$ to each term

$2y \times y^2 + 2y \times (-3y) + 2y \times 2$
$= 2y^3 - 6y^2 + 4y$

Step2: Distribute $-11$ to each term

$-11 \times y^2 + (-11) \times (-3y) + (-11) \times 2$
$= -11y^2 + 33y - 22$

Step3: Combine all expanded terms

$2y^3 - 6y^2 + 4y - 11y^2 + 33y - 22$

Step4: Combine like terms

$2y^3 + (-6y^2 -11y^2) + (4y + 33y) - 22$
$= 2y^3 -17y^2 + 37y - 22$

Answer:

$2y^3 - 17y^2 + 37y - 22$