Question

find the product and write the result in standard form.

• 3i(4i - 2)
• 3i(4i - 2) = \square

(type your answer in the form a + bi. use integers or fractions for any numbers in the expressio

Explanation:

Step1: Distribute $-3i$ to each term

$-3i(4i) + (-3i)(-2)$

Step2: Calculate each product

$(-3\times4)i^2 + 6i$

Step3: Substitute $i^2=-1$

$-12(-1) + 6i$

Step4: Simplify the real term

$12 + 6i$

Answer:

$12 + 6i$