Question

find pt, qs, and ru.
p q r s t u
-8 -6 -4 -2 0 2 4

Explanation:

Step1: Find the value of PT

The coordinate of P is - 8 and the coordinate of T is 2. The distance between two points \(x_1\) and \(x_2\) on a number - line is \(|x_2 - x_1|\). So \(PT=|2-(-8)|=|2 + 8| = 10\).

Step2: Find the value of QS

The coordinate of Q is - 4 and the coordinate of S is 0. So \(QS=|0-(-4)|=|0 + 4| = 4\).

Step3: Find the value of RU

The coordinate of R is - 2 and the coordinate of U is 4. So \(RU=|4-(-2)|=|4 + 2| = 6\).

Answer:

PT = 10, QS = 4, RU = 6