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find $\frac{h(8)}{f(-3)}$ in simplified form. $f(x)$ $g(x) = -x^2 + 3x …

Question

find $\frac{h(8)}{f(-3)}$ in simplified form.
$f(x)$
$g(x) = -x^2 + 3x - 4$

$x$$h(x)$
$4$$10$
$-3$$7$
$8$$6$
$5$$9$
$-4$$-7$

Explanation:

Step1: Find $h(8)$ from table

From the table, when $x=8$, $h(8)=6$.

Step2: Find equation of $f(x)$

The line $f(x)$ passes through $(0,2)$ and $(1,4)$. Slope $m=\frac{4-2}{1-0}=2$. Using $y=mx+b$, $b=2$, so $f(x)=2x+2$.

Step3: Calculate $f(-3)$

Substitute $x=-3$ into $f(x)$:
$f(-3)=2(-3)+2=-6+2=-4$

Step4: Compute the ratio

$\frac{h(8)}{f(-3)}=\frac{6}{-4}$

Step5: Simplify the fraction

$\frac{6}{-4}=-\frac{3}{2}$

Answer:

$-\frac{3}{2}$