Question

find the solution set.
6x² + x - 1 = 0
separate the two values with a comma.
enter the correct answer.

Explanation:

Step1: Identify quadratic formula

For $ax^2+bx+c=0$, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Step2: Assign a,b,c values

$a=6$, $b=1$, $c=-1$

Step3: Calculate discriminant

$\Delta = 1^2-4(6)(-1)=1+24=25$

Step4: Compute root 1

$x_1=\frac{-1+\sqrt{25}}{2(6)}=\frac{-1+5}{12}=\frac{4}{12}=\frac{1}{3}$

Step5: Compute root 2

$x_2=\frac{-1-\sqrt{25}}{2(6)}=\frac{-1-5}{12}=\frac{-6}{12}=-\frac{1}{2}$

Answer:

$\frac{1}{3}, -\frac{1}{2}$