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Question
find the solution set of the inequality.\\(16x - 7 \leq -71\\)\\(x\\) \\(\square\\) \\(\square\\)
Step1: Add 7 to both sides
To isolate the term with \( x \), we add 7 to both sides of the inequality \( 16x - 7 \leq -71 \). This gives us \( 16x - 7 + 7 \leq -71 + 7 \), which simplifies to \( 16x \leq -64 \).
Step2: Divide both sides by 16
Next, we divide both sides of the inequality \( 16x \leq -64 \) by 16 to solve for \( x \). So, \( \frac{16x}{16} \leq \frac{-64}{16} \), which simplifies to \( x \leq -4 \).
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\( x \leq -4 \)