Question

find the solution of the system of equations.

$8x - 10y = 28$

$4x - y = 6$

Explanation:

Step1: Isolate $y$ from second equation

Rearrange $4x - y = 6$ to solve for $y$:
$y = 4x - 6$

Step2: Substitute $y$ into first equation

Replace $y$ in $8x - 10y = 28$:
$8x - 10(4x - 6) = 28$

Step3: Simplify and solve for $x$

Expand and combine like terms:
$8x - 40x + 60 = 28$
$-32x = 28 - 60$
$-32x = -32$
$x = \frac{-32}{-32} = 1$

Step4: Substitute $x=1$ to find $y$

Use $y = 4x - 6$:
$y = 4(1) - 6 = -2$

Answer:

$x=1$, $y=-2$