Question

find the sum.
$(2x^2 + 5x - 7) + (3 - 4x^2 + 6x)$
$2x^2 + 3x + 1$
$-2x^2 - 11x - 4$
$2x^2 + 5x - 7$
$-2x^2 + 11x - 4$

Explanation:

Step1: Remove parentheses

$(2x^2 + 5x - 7) + (3 - 4x^2 + 6x) = 2x^2 + 5x - 7 + 3 - 4x^2 + 6x$

Step2: Combine like $x^2$ terms

$2x^2 - 4x^2 = -2x^2$

Step3: Combine like $x$ terms

$5x + 6x = 11x$

Step4: Combine constant terms

$-7 + 3 = -4$

Step5: Assemble simplified expression

$-2x^2 + 11x - 4$

Answer:

$-2x^2 + 11x - 4$