QUESTION IMAGE
Question
find the sum of the unit fractions.
- 1/4 + 1/4 + 1/4 =
- 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 =
- 1/6 + 1/6 + 1/6 =
- 1/10 + 1/10 + 1/10 + 1/10 + 1/10 + 1/10 + 1/10 =
- 1/2 + 1/2 =
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Response
Problem 1: $\frac{1}{4} + \frac{1}{4} + \frac{1}{4}$
Step1: Count the number of terms
There are 3 terms of $\frac{1}{4}$.
Step2: Multiply the fraction by the number of terms
$3 \times \frac{1}{4} = \frac{3}{4}$
Problem 2: $\frac{1}{8} + \frac{1}{8} + \frac{1}{8} + \frac{1}{8} + \frac{1}{8} + \frac{1}{8}$
Step1: Count the number of terms
There are 6 terms of $\frac{1}{8}$.
Step2: Multiply the fraction by the number of terms
$6 \times \frac{1}{8} = \frac{6}{8} = \frac{3}{4}$ (simplified)
Problem 3: $\frac{1}{6} + \frac{1}{6} + \frac{1}{6}$
Step1: Count the number of terms
There are 3 terms of $\frac{1}{6}$.
Step2: Multiply the fraction by the number of terms
$3 \times \frac{1}{6} = \frac{3}{6} = \frac{1}{2}$ (simplified)
Problem 4: $\frac{1}{10} + \frac{1}{10} + \frac{1}{10} + \frac{1}{10} + \frac{1}{10} + \frac{1}{10} + \frac{1}{10} + \frac{1}{10}$ (assuming 8 terms, as the original has a typo)
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s:
- $\boldsymbol{\frac{3}{4}}$
- $\boldsymbol{\frac{3}{4}}$ (or $\frac{6}{8}$)
- $\boldsymbol{\frac{1}{2}}$ (or $\frac{3}{6}$)
- $\boldsymbol{\frac{4}{5}}$ (or $\frac{8}{10}$)
- $\boldsymbol{1}$
- $\boldsymbol{\frac{3}{4}}$
- $\boldsymbol{\frac{25}{6}}$ (or $4\frac{1}{6}$)