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find the value of x. (16x)° 26° x =

Question

find the value of x.
(16x)°
26°
x =

Explanation:

Step1: Identify angle - relationship

$\angle BFD = 90^{\circ}$, and $\angle BFC=26^{\circ}$. So, $\angle CFD=\angle BFD - \angle BFC$.

Step2: Calculate $\angle CFD$

$\angle CFD = 90^{\circ}-26^{\circ}=64^{\circ}$.

Step3: Use vertical - angle property

$\angle AFE$ and $\angle CFD$ are vertical angles, so $\angle AFE=\angle CFD = 64^{\circ}$.

Step4: Solve for $x$

Since $\angle AFE=(16x)^{\circ}$, we set up the equation $16x = 64$.
Dividing both sides by 16: $x=\frac{64}{16}$.

Answer:

$4$