Question

1. find the value of x that makes p || q. (10x + 57)° (17x + 8)°

Explanation:

Step1: Use corresponding - angles postulate

When two parallel lines are cut by a transversal, corresponding angles are congruent. If \(p\parallel q\), then \((10x + 57)^{\circ}=(17x+8)^{\circ}\).

Step2: Solve the equation for \(x\)

Subtract \(10x\) from both sides of the equation \(10x + 57=17x+8\). We get \(57 = 7x+8\). Then subtract 8 from both sides: \(57 - 8=7x\), so \(49 = 7x\). Divide both sides by 7: \(x=\frac{49}{7}=7\).

Answer:

\(x = 7\)