QUESTION IMAGE
Question
find the value of ( x ). note that ( ab = x ), ( bc = 9 ), and ( cd = 16 ).
Step1: Recall the secant-secant theorem
If a secant segment $BA$ and a secant segment $BD$ are drawn from a point $B$ outside the circle, then $BA^2 = BC \times BD$.
Step2: Calculate length of BD
$BD = BC + CD = 9 + 16 = 25$
Step3: Substitute into the theorem
$x^2 = 9 \times 25$
Step4: Solve for x
$x = \sqrt{9 \times 25} = \sqrt{225} = 15$
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