find the value of a. pythagorean theorem: $a^{2}+b^{2}=c^{2}$ a = $sqrt…

$find the value of a. pythagorean theorem: $a^{2}+b^{2}=c^{2}$ a = $sqrt…$

find the value of a. pythagorean theorem: $a^{2}+b^{2}=c^{2}$ a = $sqrt{?}$

Let $b = 2$ m and $c=5$ m. The Pythagorean theorem is $a^{2}+b^{2}=c^{2}$, so $a^{2}=c^{2}-b^{2}$.

$a^{2}=5^{2}-2^{2}=25 - 4$.

$a^{2}=21$.

$a=\sqrt{21}$ m.

$\sqrt{21}$ m