Question

find the value of b. pythagorean theorem: a^2 + b^2 = c^2 b = \sqrt{?} 8 ft 15 ft b

Explanation:

Step1: Identify values for Pythagorean theorem

Let $a = 8$, $c=15$. According to $a^{2}+b^{2}=c^{2}$, we can solve for $b$.

Step2: Rearrange the formula for $b$

$b^{2}=c^{2}-a^{2}$. Substitute $a = 8$ and $c = 15$ into the formula: $b^{2}=15^{2}-8^{2}$.

Step3: Calculate the values

$15^{2}=225$, $8^{2}=64$. Then $b^{2}=225 - 64=161$.

Step4: Find the value of $b$

$b=\sqrt{161}$.

Answer:

$\sqrt{161}$