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if $fj = p$ and $hj = 2p - 38$, find the value of $p$ in rhombus $fghi$.

Question

if $fj = p$ and $hj = 2p - 38$, find the value of $p$ in rhombus $fghi$.

Explanation:

Step1: Set equal segments (rhombus diagonals)

In a rhombus, diagonals bisect each other, so $FJ = HJ$. Substitute the given expressions:
$p = 2p - 38$

Step2: Solve for $p$

Subtract $p$ from both sides, then simplify:
$0 = p - 38$
$p = 38$

Answer:

$38$