QUESTION IMAGE
Question
first graph the equations, and then mark the point of intersection.
$y = -dfrac{1}{6}x + 3$
$y = -dfrac{2}{3}x$
Step1: Set equations equal
To find the intersection, set $-\frac{1}{6}x + 3=-\frac{2}{3}x$.
Step2: Multiply by 6 to eliminate denominators
Multiply each term by 6: $-x + 18=-4x$.
Step3: Solve for x
Add $4x$ to both sides: $3x + 18 = 0$. Subtract 18: $3x=-18$. Divide by 3: $x = -6$.
Step4: Substitute x into one equation
Substitute $x = -6$ into $y = -\frac{2}{3}x$: $y=-\frac{2}{3}(-6)=4$.
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The point of intersection is $(-6, 4)$.