Question

first up, lets review the assignments learning objectives. get familiar with this topic by reviewing instruction and answering a couple of questions. question the width of a proton is 1 × 10^(-5) of the width of an atom. convert this number to decimal form. provide your answer below:

Explanation:

Step1: Recall negative - exponent rule

For a non - zero number \(a\) and integer \(n\), \(a^{-n}=\frac{1}{a^{n}}\). Here \(a = 10\) and \(n = 5\), so \(10^{-5}=\frac{1}{10^{5}}\).

Step2: Calculate \(10^{5}\)

\(10^{5}=10\times10\times10\times10\times10 = 100000\).

Step3: Find the decimal form

\(1\times10^{-5}=\frac{1}{100000}=0.00001\).

Answer:

\(0.00001\)