Question

first we must set up our equa using the pythagorean the
$a^{2}+b^{2}=c^{2}$
$4^{2}+b^{2}=13^{2}$
$16 + b^{2}=169$
$b^{2}=?$
hint: subtract the value of 16 from 169

Explanation:

Step1: Isolate $b^{2}$

We start with the equation $16 + b^{2}=169$. By the subtraction - property of equality, we subtract 16 from both sides of the equation.
$b^{2}=169 - 16$

Step2: Calculate the right - hand side

$169-16 = 153$

Answer:

$153$