Question

the following figure is a rectangle made up of two smaller rectangles. (a) find the area of the following (in square units). the light rectangle (on the left): the dark rectangle (on the right): (b) give the area of the entire figure (in square units) in two different ways. as a sum of two areas: as a product of the length and width:

Explanation:

Step1: Recall area formula for rectangle

The area formula for a rectangle is $A = l\times w$, where $l$ is the length and $w$ is the width.

Step2: Find area of light - colored rectangle

The length of the light - colored rectangle is 7 and the width is 1. So, $A_1=7\times1 = 7$.

Step3: Find area of dark - colored rectangle

The length of the dark - colored rectangle is 7 and the width is 4. So, $A_2=7\times4 = 28$.

Step4: Find area of entire figure as a sum

The area of the entire figure as a sum of the two areas is $A = A_1+A_2=7 + 28=35$.

Step5: Find area of entire figure as a product

The length of the entire rectangle is 7 and the width is $1 + 4=5$. So, $A=7\times(1 + 4)=7\times5 = 35$.

Answer:

The light rectangle (on the left): 7
The dark rectangle (on the right): 28
As a sum of two areas: 35
As a product of the length and width: 35