Question

following figure is a rectangle made up of two smaller rectangles.
(a) find the area of the following (in square units).
the light rectangle (on the left):
the dark rectangle (on the right):
(b) give the area of the entire figure (in square units) in two different ways.
as a sum of two areas:
as a product of the length and width:

Explanation:

Step1: Calculate light rectangle area

Area = length × width = $7 \times x = 7x$

Step2: Calculate dark rectangle area

Area = length × width = $7 \times 4 = 28$

Step3: Sum the two areas

Total area = $7x + 28$

Step4: Calculate total area as product

Total width = $x + 4$, height = 7, so area = $7(x + 4)$

Answer:

(a)
The light rectangle (on the left): $7x$
The dark rectangle (on the right): $28$

(b)
As a sum of two areas: $7x + 28$
As a product of the length and width: $7(x + 4)$