Question

formation of butane from carbon dioxide and water balanced equation most chemical reactions are considered reversible but are often only thermodynamically favorable in one direction. consider the compound butane for this set of questions. the formula for butane is c₄h₁₀. which of the following equations represents the reaction in which butane and oxygen are formed from carbon dioxide and water? 8co₂(g) + 10h₂o(g) → 2c₄h₁₀(g) + 13o₂(g) c₄h₁₀(g) + o₂(g) → co₂(g) + h₂o(g) co₂(g) + h₂o(g) → c₄h₁₀(g) + o₂(g) c₄h₁₀(g) + 6o₂(g) → 4co₂(g) + 5h₂o(g)

Explanation:

To determine the correct equation, we analyze the reactants and products. The problem asks for the reaction where butane ($\ce{C4H10}$) and oxygen ($\ce{O2}$) are formed from carbon dioxide ($\ce{CO2}$) and water ($\ce{H2O}$).

1. Analyze each option:

• Option 1: $\ce{8CO2(g) + 10H2O(g) -> 2C4H10(g) + 13O2(g)}$: Reactants are $\ce{CO2}$ and $\ce{H2O}$, products are $\ce{C4H10}$ and $\ce{O2}$. Let's check atom balance.
• Carbon: Left - 8, Right - $2\times4 = 8$ (balanced).
• Hydrogen: Left - $10\times2 = 20$, Right - $2\times10 = 20$ (balanced).
• Oxygen: Left - $(8\times2)+(10\times1)=16 + 10 = 26$, Right - $(2\times0)+(13\times2)=26$ (balanced).
• Option 2: $\ce{C4H10(g) + O2(g) -> CO2(g) + H2O(g)}$: Reactants are $\ce{C4H10}$ and $\ce{O2}$, products are $\ce{CO2}$ and $\ce{H2O}$. This is combustion (butane reacting with oxygen), not formation from $\ce{CO2}$ and $\ce{H2O}$.
• Option 3: $\ce{CO2(g) + H2O(g) -> C4H10(g) + O2(g)}$: Unbalanced (e.g., C: 1 vs 4; H: 2 vs 10; O: 3 vs 2).
• Option 4: $\ce{C4H10(g) + 6O2(g) -> 4CO2(g) + 5H2O(g)}$: Reactants are $\ce{C4H10}$ and $\ce{O2}$, products are $\ce{CO2}$ and $\ce{H2O}$ (combustion, not formation from $\ce{CO2}$ and $\ce{H2O}$).

Only Option 1 has $\ce{CO2}$ and $\ce{H2O}$ as reactants and $\ce{C4H10}$ and $\ce{O2}$ as products, and is balanced.

Answer:

A. $\ce{8CO2(g) + 10H2O(g) -> 2C4H10(g) + 13O2(g)}$