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francis - 8 - science 7 - (2421917) quiz: speed and velocity due sep 26…

Question

francis - 8 - science 7 - (2421917)
quiz: speed and velocity
due sep 26 - 11:45 pm late
it takes mikayla 300 seconds to walk to her friend carla’s house at a constant speed. first, she walks up her street, moving from south to north. at the end of her street, she turns right and starts moving from north to east, continuing to travel at the same speed until she reaches carla’s house.
when mikayla returns home, she walks along her original path, moving at the same speed. how long does it take mikayla to return home? what is her velocity for the entire trip starting from home, going to carla’s house, and returning home? explain how you can determine her velocity.

Explanation:

Step1: Analyze time for return trip

Since she moves at the same speed and along the same path on the return - trip, the time taken for the return trip is the same as the time taken to go to Carla's house. So the time to return home is 300 seconds.

Step2: Define velocity formula

Velocity is defined as $\text{Velocity}=\frac{\text{Displacement}}{\text{Time}}$. Displacement is the straight - line distance from the initial to the final position.

Step3: Determine displacement for the entire trip

When she starts from home, goes to Carla's house, and then returns home, her initial and final positions are the same. So the displacement for the entire trip is 0.

Step4: Calculate velocity for the entire trip

Using the velocity formula $\text{Velocity}=\frac{\text{Displacement}}{\text{Time}}$, with displacement = 0 and total time $t = 300+300=600$ seconds, we have $\text{Velocity}=\frac{0}{600}=0$.

Answer:

It takes 300 seconds to return home. Her velocity for the entire trip is 0. We can determine her velocity by using the formula $\text{Velocity}=\frac{\text{Displacement}}{\text{Time}}$. Since the initial and final positions are the same for the entire round - trip, the displacement is 0, resulting in a velocity of 0.