Question

frank has 23 bags of candy with 25 pieces of candy in each. juan has 48 bags of candy with 19 pieces of candy in each. brad has 33 bags of candy with 31 pieces of candy in each. 1. how many pieces of candy do frank and brad have together? 2. how many pieces of candy do all three friends have combined? 3. how many more pieces of candy does juan have than frank? 4. how many more pieces of candy do brad and frank have than juan? 5. who has a number of pieces of candy with a 1 with a value of 1,000? 6. name a number that is greater than juans number of candies but fewer than brads number of candies. 7. if frank divides his candy equally between himself and his 4 best friends, how many pieces will each of them receive? 8. if brad divides his pieces of candy equally into 6 equal groups, how many remaining pieces of candy will brad have? 9. which two friends have a total of 1,487 pieces of candy? 10. if each piece of candy has a total value of 6 cents, what is the value of juans candy?

Explanation:

Sub - question 1:

Step 1: Calculate Frank's candies

Frank has 23 bags with 25 pieces each. So, Frank's candies = \(23\times25 = 575\)

Step 2: Calculate Brad's candies

Brad has 33 bags with 31 pieces each. So, Brad's candies = \(33\times31=1023\)

Step 3: Sum Frank and Brad's candies

Total candies = \(575 + 1023=1598\)

Step 1: Calculate Juan's candies

Juan has 48 bags with 19 pieces each. So, Juan's candies = \(48\times19 = 912\)

Step 2: Use Frank and Brad's candies from Q1

Frank: 575, Brad: 1023

Step 3: Sum all three

Total = \(575+912 + 1023=2510\)

Step 1: Get Juan's (912) and Frank's (575) candies

Step 2: Subtract Frank's from Juan's

Difference = \(912-575 = 337\)

Answer:

1598

Sub - question 2: