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fred has $400 in his checking account. each month, $45 is automatically…

Question

fred has $400 in his checking account. each month, $45 is automatically deducted from his account to pay for his cell phone plan. he makes no other deposits or withdrawals. he wants to always have more than $100 in his account. what is the greatest number of months he can pay for his cell phone and still have more than $100 in his account?
7 months
8 months
9 months
10 months

Explanation:

Step1: Define the variable

Let \( n \) be the number of months.

Step2: Set up the inequality

The initial amount is $450, and each month $40 is deducted. We want the amount left to be more than $100. So the inequality is \( 450 - 40n > 100 \).

Step3: Solve the inequality

Subtract 450 from both sides: \( - 40n > 100 - 450 \) which simplifies to \( - 40n > - 350 \).
Divide both sides by - 40 (and remember to reverse the inequality sign): \( n < \frac{350}{40} = 8.75 \).
Since \( n \) represents the number of months, it must be a whole number. So the greatest whole number less than 8.75 is 8? Wait, no, wait. Wait, let's check the calculation again. Wait, 450 - 40n > 100. So 450 - 100 > 40n. 350 > 40n. Then \( n < \frac{350}{40}=8.75 \). But wait, maybe I made a mistake. Wait, let's test with 9 months. 450 - 409 = 450 - 360 = 90? No, that's less than 100. Wait, wait, no, wait 450 - 409 = 450 - 360 = 90? Wait, that's not right. Wait, maybe the initial amount is $490? Wait, the problem says "Rod has $490 in his checking account". Oh! I misread the initial amount. Let's correct that.

Step1: Correct the initial amount

Rod has $490, not $450. Let \( n \) be the number of months.

Step2: Set up the correct inequality

The amount left after \( n \) months is \( 490 - 40n \), and we want this to be more than $100. So \( 490 - 40n > 100 \).

Step3: Solve the correct inequality

Subtract 490 from both sides: \( - 40n > 100 - 490 \) which is \( - 40n > - 390 \).
Divide both sides by - 40 (reverse the inequality): \( n < \frac{390}{40}=9.75 \).
Since \( n \) must be a whole number, the greatest integer less than 9.75 is 9. Let's check: 490 - 409 = 490 - 360 = 130, which is more than 100. 490 - 4010 = 490 - 400 = 90, which is less than 100. So the greatest number of months is 9.

Answer:

9 months