Question

the function f is defined as follows. f(x)=\sqrt3{x}+2 find f(343) and f( - 125). f(343)= f( - 125)=

Explanation:

Step1: Substitute $x = 343$ into $f(x)$

$f(343)=\sqrt[3]{343}+2$
Since $\sqrt[3]{343}=7$ (because $7\times7\times7 = 343$), then $f(343)=7 + 2$.

Step2: Calculate $f(343)$

$f(343)=9$

Step3: Substitute $x=-125$ into $f(x)$

$f(-125)=\sqrt[3]{-125}+2$
Since $\sqrt[3]{-125}=-5$ (because $(-5)\times(-5)\times(-5)=-125$), then $f(-125)=-5 + 2$.

Step4: Calculate $f(-125)$

$f(-125)=-3$

Answer:

$f(343)=9$
$f(-125)=-3$