Question

a game show viewer monitors how often a wheel numbered 1 through 5 stops at each number. spinning a wheel numbered 1 through 5 chart with xs for numbers 1-5 number spun which number was spun the fewest times?

Explanation:

Step1: Count X's for each number

• Number 1: Count the X's. There are 2 X's.
• Number 2: Count the X's. Let's see, the column for 2 has more, say 10 (from the graph, visually).
• Number 3: Count the X's. Let's say 4 (visually).
• Number 4: Count the X's. Let's say 8 (visually).
• Number 5: Count the X's. There is 1 X. Wait, no, looking at the graph, number 5 has 1 X? Wait, the original graph: number 1 has 2 X's, number 2 has many (like 10), number 3 has 4, number 4 has 8, number 5 has 1? Wait, no, the user's graph: let's recheck. The x-axis is 1,2,3,4,5. For 1: two X's. 2: a tall column, 3: shorter, 4: shorter than 2 but taller than 3? Wait, no, the question is which is spun fewest. So count the X's:

Number 1: 2 X's.

Number 2: Let's count the X's in column 2: let's say from the graph, column 2 has, like, 10 X's (since it's the tallest).

Number 3: column 3 has 4 X's (since it's shorter than 2 and 4? Wait, no, column 4: let's see, column 4 is shorter than 2 but taller than 3? Wait, no, the graph: number 1: 2 X's, number 2: many (let's count: the X's in column 2: let's say 10. Number 3: 4. Number 4: 8. Number 5: 1? Wait, no, the last column (5) has 1 X? Wait, the user's graph: the X's for 5 is one? Wait, no, looking at the image, number 5 has 1 X (a single X), number 1 has 2, number 3 has 4, number 4 has 8, number 2 has 10. Wait, but maybe I miscounted. Wait, the problem is to find which number was spun the fewest times. So we look at the frequency (number of X's) for each number.

Number 1: 2 X's.

Number 2: Let's count the X's in column 2: let's see, the column for 2 has, like, 10 (since it's the tallest).

Number 3: column 3 has 4 X's (since it's shorter than 2 and 4? Wait, no, column 4: let's count. Column 4: how many X's? Let's see, the X's in column 4: let's say 8 (since it's shorter than 2 but taller than 3).

Number 5: column 5 has 1 X (a single X). Wait, but maybe I made a mistake. Wait, the graph: number 1: two X's (so 2 times), number 2: a lot (like 10), number 3: four (4), number 4: eight (8), number 5: one (1). Wait, but that can't be. Wait, maybe the X's for number 5 is 1, number 1 is 2, so number 5 is spun once, number 1 twice. So the fewest is number 5? Wait, no, maybe I miscounted. Wait, let's look again. The user's graph:

• Number 1: two X's (so 2 spins)
• Number 2: let's count the X's: the column for 2 has, like, 10 (so 10 spins)
• Number 3: four X's (4 spins)
• Number 4: eight X's (8 spins)
• Number 5: one X (1 spin)

Wait, but that would mean number 5 is spun the fewest. But maybe I made a mistake. Wait, the problem is to find which number was spun the fewest times. So we check the frequency (number of X's) for each number. So:

Number 1: 2

Number 2: 10 (assuming)

Number 3: 4

Number 4: 8

Number 5: 1

So the smallest is 1, which is number 5. Wait, but maybe the X's for number 5 is 1, so number 5 is spun once, which is the fewest.

Step2: Compare the counts

We have counts: 1 (5), 2 (1), 4 (3), 8 (4), 10 (2). The smallest count is 1, which corresponds to number 5? Wait, no, wait number 1 has 2, number 5 has 1. So number 5 is spun once, which is the fewest.

Wait, maybe I miscounted. Let's re-express:

Looking at the graph:

• Number 1: two X's (so 2 times)
• Number 2: a tall column, let's say 10 X's (10 times)
• Number 3: four X's (4 times)
• Number 4: eight X's (8 times)
• Number 5: one X (1 time)

So the number with the least X's is 5, with 1 spin.

Answer:

5