Question

give the systematic name of each of the compounds.
fecl₂:
pbo₂:
cubr:
au₂s₃:

Explanation:

1. For $FeCl_2$, iron has a +2 oxidation - state in this compound, so it is named iron(II) chloride.
2. In $PbO_2$, lead has a +4 oxidation - state, and it is named lead(IV) oxide.
3. For $CuBr$, copper has a +1 oxidation - state, and it is named copper(I) bromide.
4. In $Au_2S_3$, gold has a +3 oxidation - state, and it is named gold(III) sulfide.

Answer:

1. Iron(II) chloride
2. Lead(IV) oxide
3. Copper(I) bromide
4. Gold(III) sulfide